tracydundun@tracydundun-laptop:~/scripts$ number=2*3-3
tracydundun@tracydundun-laptop:~/scripts$ echo $number
2*3-3
tracydundun@tracydundun-laptop:~/scripts$ echo "$number"
2*3-3
tracydundun@tracydundun-laptop:~/scripts$ declare -i number=2*2-1
tracydundun@tracydundun-laptop:~/scripts$ echo $number
3
tracydundun@tracydundun-laptop:~/scripts$ more declare.sh
#writen at 7.2
#for declare
numebr1=2*3+2*3-4
declare number2=2*3+2*3-4
echo $number1
echo $number2
tracydundun@tracydundun-laptop:~/scripts$ sh declare.sh
declare.sh: 4: declare: not found

please tell me why "declare.sh:4:declare:not found"
thak you!!

declare后面要加数据类型

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代码:

declare -i number2=2*3+2*3-4

Thank you !
But when I add the "-i" to it,the result is also wrong!

有哪不对劲吗？
贴代码看看

tracydundun@tracydundun-laptop:~/scripts$ more declare.sh
#writen at 7.2
#for declare
numebr1=2*3+2*3-4
declare -i number2=2*3+2*3-4
echo $number1
echo $number2
tracydundun@tracydundun-laptop:~/scripts$ sh declare.sh
declare.sh: 4: declare: not found


tracydundun@tracydundun-laptop:~/scripts$

你用的什么shell
我这边bash是没有问题的。

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代码:

file $(which sh)

tracydundun@tracydundun-laptop:~$ echo $0
bash
The same as yours!

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代码:

type declare

你这个declare是用的内部命令吗？
numebr1=2*3+2*3-4
这个应该是写错了吧，number1